Branislav Djurasevic
Polish Chess Federation
2018
White wins
1. d6 1. Kc6? b3! 2. Kxb5 b2 = 1... b3
Thematic try 1: 2. Nxb3? Rxb3 3. Rc5 Kf6! 3... Rf3? 4. Kc8! Rd3 5. d7 Ke7 6. Rc7! +- 4. Kc7 Rd3! 5. d7 Ke7! 6. Re5+ Kf6
7. Re3! Rd2(4) 8. d8=Q+ Rxd8 9. Kxd8 f4/Kg5 =
Thematic try 2: 2. Nd3? b2! 3. Nxb2 Rxb2 4. Rc5 Kf6! 4... Rf2? 5. Kc8! Rd2 6. d7 Ke7 7. Rc7! +- 5. Kc7 Rd2! 6. d7 Ke7! 7. Re5+ Kf6
8. Re2! Rd3(4) 9. d8=Q+ Rxd8 10. Kxd8 f4/Kg5 =
Solution: 2. Ne2!! b2 3. Nc3 b1=Q 3... Rb3 4. Nb1! +- 4. Nxb1 Rxb1 5. Rc5! Necessary quiet move. 5... Kf6 6. Kc7! 6. Kc8? Rd1 (or 6... Kg5 7. d7 Rd1) 7. d7 Kg5! 8. d8=Q+ Rxd8+ 9. Kxd8 Kg4! = 6... Rd1 7. d7 Ke7 7... Kg5 8. Rc6! another quiet move (8. Kc6?! Kf6! 9. Rd5? Rxd5 10. Kxd5 Ke7 =) 8... f4 (8... Rxd7+ 9. Kxd7 +-) 9. Rd6 +- 8. Re5+ Kf6
9. Re1!! Crucial white move. 9. Re8? f4! = 9... Rd2 10. d8=Q+ Rxd8 11. Kxd8 +-
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Branislav Djurasevic
EG 2016-2017
2017
2nd Prize
White wins
1. g8=Q+ Kc7 2. Nd5+ Kb8 3. Qg3+
a) 3... Nf4! play for stalemate 4. Qxf4+ Ka8 5. Nc7+ 5. axb7+? Kxb7 6. Qb4+ Ka8 7. Nb6+ Bxb6+ 8. Qxb6 Qxc5+! 9. Qxc5 b1=Q = 5... Qxc7+ 6. Qxc7 b1=Q 7. axb7+ 7. Qd8+? Bb8 8. axb7+ Ka7 = 7... Qxb7 8. Qd8+ Bb8
9. Bd5 Ka7! 10. Qb6+! 10. Bxb7? Bc7+! 11. Qxc7= stalemate 10... Qxb6+ 11. cxb6#
b) 3... Ka8 4. Nc7+ Qxc7+ 5. Qxc7 b1=Q 6. axb7+ 6. Qd8+? Bb8 7. axb7+ Ka7! = 6... Qxb7 7. Qd8+ Bb8
8. Bd5 Nxc5 9. Qg8! 9. Bxb7+?? Nxb7+ -+; 9. Qg5?? Bc7# 9... Nb3+ 10. Ka4 Nc5+ 11. Ka3 +-
"Ideal mate with block on b8. Author has managed to improve a nice stalemate idea by Maurice Ashley (see "Game Studies" by Siegfried Hornecker, EG iv2017). In the first main line, Black sacrifices the knight in order to realize this stalemate. Thanks to the added white pawn, White forces an ideal mate with block on b8. In the second main line, the bS plays an active role, but White can find better places for Q and K." (Judge M. Minski)
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Branislav Djurasevic
Moscow Ty
2018
Special Honourable Mention
White wins
1. fxe7! 1. dxe7? Bg8! (or 1... Rf3 2. e8=Q+ Bg8+ = moves inversion. The same as after 1....Bg8! in try.; 1... Rxf6? 2. e8=Q+ Bg8 3. Qe4! Bd5!? (3... Be6 4. Qa8+! (4. Qh1+? Kg8 5. Qa8+ Rf8 6. Qc6 Bf7! 7. gxf7+ Kxf7! = (7... Rxf7? 8. Qe6! +-)) 4... Bg8 5. Qh1+ Bh7 6. Qxh7#) 4. Qxd5 Rxg6 5. Qa8+! (5. Qh5+? Rh6 =) 5... Kh7 6. Qe4! Kh6 7. Qh4#) 2. e8=Q Rf3+! 3. Kb4 Rf4+ 4. Kc5 Rf5+ 5. Kd4 Rf4+ 6. Ke5 (6. Ke3 Rxf6! 7. Qe4? Re6 -+) 6... Rxf6! = White king could not escape from perpetual check coming on 6th rank or e file. 1... Bg8! Black plays on stalemate! 1... Rf3? 2. Kb4! The king can cross the 4th rank! 2... Bg8 3. d7! +- 2. d7! Rf4! Black does not allow white king to cross 4th rank and predicting to check on 4th rank after white promotes any of his pawns to queen. 2... Rd1? 3. e8=Q! Rd3+ 4. Kb4 Rb3+ 5. Kc5! Rc3+ 6. Kd6! Rd3+ 7. Kc7 Rc3+ 8. Kd8 Rc8+ 9. Ke7 Rxe8+ 10. Kxe8 +-; 2... Re1? 3. d8=Q! Re3+ 4. Kb4 Rb3+ 5. Ka5 Ra3+ 6. Kb6 Rb3+ 7. Ka6 Ra3+ 8. Qa5 +-
3. d8=N!! But white has another ace up in his sleeve! 3. d8=Q? Ra4+! 4. Kb2 Rb4+! 5. Kc3 Rb3+! (5... Rc4+? 6. Kd3 Rc3+ 7. Ke2! Rc2+ (7... Re3+ 8. Kd2 Re2+ 9. Kc3 Rc2+ 10. Kb4! Rb2+ 11. Ka5 +-) 8. Qd2! +- (8. Ke1? Rc1+! (8... Re2+? 9. Kd1! +-) 9. Qd1? Rxd1+ 10. Kxd1 Bb3+ -+)) 6. Kd2 (6. Kd4 Rd3+ =) 6... Rb2+ 7. Kd1 Rb1+ 8. Ke2 Re1+ =; 3. e8=Q? Ra4+! 4. Kb2 Rb4+! (or 4... Ra2+! 5. Kc3 Rc2+! 6. Kd4 Rc4+! =) 5. Kc3 Rc4+! = (5... Rb3+? 6. Kd4! Rb4+ 7. Kc5! +-) 3... Rf8!? 3... Re4 4. Nf7+! And now white uses the bad position of black bishop who blocks his king. 4... Bxf7 5. gxf7 +- 4. exf8=N! +- 4. exf8=B? Bd5! 5. Bd6 Kg8! (5... Be4? 6. Nf7+ Kg8 7. Ne5 +-) 6. Kb4 Be4 =
Unexpectedly only two promoted knights bring a win for white because the black king stays in prison. Short, but very intensive study; every single move deserves exclamation mark with rich play in between. (Judge: S. Osintsev)
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Branislav Djurasevic
11th Jenever JT
2018
Prize
Draw
1. f4 For White it is more important to save the e-pawn instead of the f-pawn. 1. Kd2? Nxe5 -+ 1... Kg3 Active play to attack f4.
Thematic try: 2. Kd2? Nxf4! 3. Nxf4 Kxf4 4. Ng6+ Ke4! 4... Kf5 also wins 5. Ne7+ Kxe5 6. Nc6+ (6. Ke3 a6! -+) 6... Kf4 7. Nxa7 (7. Ke2 Kg3 8. Kf1 a6! -+ And the f pawn decides.) 7... Kg3 8. Ke2 Kg2! -+ with a similar final position 5. Nh8 Kxe5 6. Nxf7+ Kd5! 7. Nh8 a5 8. Ng6 Ke4! 9. Ne7 a4 10. Nc6 a3 11. Nb4 Kf3! 12. Ke1 Kg2! -+
Solution: 2. Ke2! It is curious that the White king has to protect the king side, but not the queenside. Black's pawn on a7 will be stopped by white knight which even twice moves to the opposite side corner to reach on time. 2... Nxf4+ 3. Nxf4 Kxf4 4. Ng6+! Now the role of the e-pawn is obvious because the knight cannot be taken. 4... Ke4! 4... Kf5 5. Ne7+ Kxe5 6. Nc6+ =
5. Nh8! Thematic move 5... Kxe5 6. Nxf7+ Kd5
7. Nh8! Thematic move once more 7. Nxh6? Ke6! -+ 7... a5 8. Ng6 Ke4 8... a4 9. Nf4+! Kc4 10. Nd3 a3 11. Nc1 = and White is just on time. 9. Ne7 a4 10. Nc6 a3 11. Nb4 =
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Branislav Djurasevic
Krug-50 JT (Section A)
2017
3rd Prize
White win
1. f6! 1. Bc3? Kb3 2. f6 Bc4! = Pawn h7 is now ready to run! 1... Bh5 2. Bc3 2. Bb6? Kb4 = 2... Kb3 3. Bxa5 Kxa4 4. Bc3! Preventive protection of the b2 pawn.
a) 4... Kb3! 5. Kf8! Bg6 5... Kc4 6. Kg8! Immediately losing a tempo 6... Bg6 7. Kg7+- See the main line. 6. Kg7 Kc4
cyclic zugzwang (WTM)
In order to win, white needs to reach the same position but with the other side to move! To achieve this, white uses a seven-move-long manoeuvre. 7. Bd2! 7. Be5?! Kb3 zugzwang Position X' 7... Kb3 8. Bc1 Kb4 8... Kc2? 9. b4! +- 9. Bf4! Kc4 10. Bd6! Kd5 10... Kd4? 11. f7! Bxf7 12. Kxf7 +- 11. Bb4! Kd4 11... Ke6? 12. Bc3 Be8 13. Kxh7 +- Two pawns up is a technical win for white.; 11... Kc4? 12. Bc3! +- 12. Be1!! The crucial and the fastest move for losing another tempo. 12. Ba5?! Waste of time. 12... Kd5 13. f7? Bxf7 14. Kxf7 h5 15. Kg6 h4 = 12... Kc4 12... Kd5 13. f7! Bxf7 14. Kxf7 h5 15. Kg6 h4 16. Bxh4 +- 13. Bc3!
cyclic zugzwang (BTM)
13... Kb3 13... Kd5 14. f7! Bxf7 15. Kxf7 h5 16. Bf6 +- 14. Be5! Position X zugzwang The bishop controls both b2 and h2. 14... Kc4 15. f7! Finally this move works! 15... Bxf7 16. Kxf7 +- e.g. 16... h5 17. Kg6 h4 18. Kg5 h3 19. Kg4 h2 20. Bxh2 Kb3 21. Be5 +-
b) 4... Bg6 5. f7! Bxf7 6. Kxf7 h5 7. Ke6 h4 And we reach a position from a study by G. Zakhodyakin, 64, (1934), ID=68578 in hhdbv.
8. Kd5 h3 9. Kc4 h2 10. Bb4 h1=Q 11. b3#
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Branislav Djurasevic
UP-25
2018
1st Commendation
Draw
1. Bc6! 1. Bd7? Kxb3 (or 1... Bc3+ 2. Kb1 Kxb3) 2. Be6 Bc3+! 3. Kb1 Kb4 4. h6 Nd2+! 5. Kc2 Ne4/Nf3 -+ 1... Kxb3 2. Bd5! Kc3! 2... Bc3+ 3. Kb1 Kb4! 4. h6! (4. Bg8? Nd2+/Na3+ 5. Kc2 h6! -+) 4... Kb3 5. Kc1! Bd2+ 6. Kd1! =)
3. Bg8!! 3. Bxc4? Kxc4 -+; 3. h6? Kb3!! 4. Kb1 Bd2! 5. Bg8 Bxh6 6. Bxh7 Na3+ 7. Ka1 Bg7# 3... Nd2! 3... h6 4. Bxc4!! = 4. h6! 4. Bxh7? Kb3! 5. Bg8+ Ka3 6. h6 Bc3# 4... Bf8 5. Ka2! Bxh6 6. Bxh7 =
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